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  1. import re
  2.  
  3. myText = 'brb some sample text I lov u. I need some $$ for 2mw.'
  4.  
  5. dictionary = {
  6.   'brb': 'be right back',
  7.   'lov u': 'love you',
  8.   '$$': 'money',
  9.   '2mw': 'tomorrow'
  10. }
  11.  
  12. pattern = re.compile(r'(?<!\w)(' + '|'.join(re.escape(key) for key in dictionary.keys()) + r')(?!\w)')
  13.  
  14. print(pattern)
  15. result = pattern.sub(lambda x: dictionary[x.group()], myText)
  16.  
  17. print(result)
Success #stdin #stdout 0.01s 7124KB
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stdin
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Standard input is empty
stdout
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<_sre.SRE_Pattern object at 0x2b4c4c7d6030>
be right back some sample text I love you. I need some money for tomorrow.
https://ideone.com/xi1xPN
language:
Python (cpython 2.7.16)
created:
3 years ago
visibility:
public

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