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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4. 	//関数の中だけを書き換えてください
  5. 	//回文になっているとき１を返す
  6. 	//回文になっていないとき０を返す
  7. 	int i,count;
  8. 	count=0;
  9. 	for(i=0;s[i]!='\0';i++){
  10. 		count++;
  11. 	}
  12. 	char t[100];
  13. 	t[count]='\0';
  14. 	int count2;
  15. 	count2=count;
  16. 	for(i=0;i<count2;i++){
  17. 		t[i]=s[count-1];
  18. 		count--;
  19. 	}   //ここまでok
  20. 	for(i=0;s[i]==t[i];i++){
  21. 		if(s[i]==t[i])return 1;
  22. 		printf("s[i]=%c,t[i]=%c\n",s[i],t[i]);
  23. 	}
  24. 	return 0;
  25. }
  26.  
  27. //メイン関数は書き換えなくてよいです
  28. int main(){
  29.     char s[100];
  30.     scanf("%s",s);
  31.     printf("%s -> %d\n",s,isPalindrome(s));
  32.     return 0;
  33. }
  34.  
Success #stdin #stdout 0s 5292KB
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https://ideone.com/jRjTpT
language:
C (gcc 8.3)
created:
56 days ago
visibility:
public

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