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  1. ///0-0 : what is your motivation, quan606303?
  2. ///quan606303 : Hutao
  3. /*idea :
  4.  
  5.  
  6.  
  7. */
  8. #include <bits/stdc++.h>
  9. #define int long long
  10. #define ll long long
  11. #define INTMAX INT_MAX
  12. #define INTMIN INT_MIN
  13. #define LONGMAX LLONG_MAX
  14. #define LONGMIN LLONG_MIN
  15. #define fi first
  16. #define se second
  17. #define memfull(a,b) memset(a,b,sizeof(a));
  18. #define endl '\n'
  19. #define file(a) freopen(a".inp","r",stdin); freopen(a".out","w",stdout);
  20. using namespace std;
  21. const int MOD=1e9+7;
  22. const int maxn=1e6+7;
  23. int n;
  24. int max_num(int x)
  25. {
  26. int maxx=0;
  27. while (x!=0)
  28. {
  29. maxx=max(maxx,x%10);
  30. x/=10;
  31. }
  32. return maxx;
  33. }
  34. int len(int x)
  35. {
  36. int cnt=0;
  37. while (x!=0)
  38. {
  39. x/=10;
  40. cnt++;
  41. }
  42. return cnt;
  43. }
  44. void sub1()
  45. {
  46. int ans=0;
  47. while (n!=0)
  48. {
  49. ans++;
  50. n-=max_num(n);
  51. }
  52. cout<<ans;
  53. }
  54. pair<int,int> dp[10][maxn];
  55. int p[15];
  56. void sub2()
  57. {
  58. for (int digit=0;digit<=9;digit++)
  59. {
  60. for (int i=0;i<maxn;i++)
  61. {
  62. int cnt=max(digit,max_num(i));
  63. if (i-cnt<=0)dp[digit][i]={1,i-cnt};
  64. else dp[digit][i]={dp[digit][i-cnt].fi+1,dp[digit][i-cnt].se};
  65. }
  66. }
  67. int ans=0;
  68. while (n!=0)
  69. {
  70. //cout<<n<<endl;
  71. int cnt=n;
  72. int left=cnt%1000000;
  73. int right=cnt/1000000;
  74. int tam=max_num(right);
  75. pair<int,int> cnt2=dp[tam][left];
  76. //cout<<cnt2.fi<<" "<<cnt2.se<<" "<<tam<<" "<<left<<endl;
  77. ans+=cnt2.fi;
  78. cnt=right*1000000+cnt2.se;
  79. n=cnt;
  80. }
  81. cout<<ans;
  82. }
  83. int32_t main()
  84. {
  85. ios_base::sync_with_stdio(0);
  86. cin.tie(0);
  87. cout.tie(0);
  88. file("DIGIT");
  89. cin>>n;
  90. sub2();
  91.  
  92. return 0;
  93. }
Success #stdin #stdout 0.2s 160052KB
stdin
Standard input is empty
stdout
Standard output is empty