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  1. n=int(input())
  2. l=[]
  3. u=[]
  4. a=[]
  5. while n:
  6. 	l.append(n%10)
  7. 	n//=10
  8. 	u.append(0)
  9. 	a.append(0)
  10. n=len(l)
  11. def backtracking(k):
  12. 	if k==n:
  13. 		for i in a:
  14. 			print(i,end="")
  15. 		print()
  16. 	else:
  17. 		for i in range(n):
  18. 			if u[i]==0:
  19. 				a[k]=l[i]
  20. 				u[i]=1
  21. 				backtracking(k+1)
  22. 				a[k]=0
  23. 				u[i]=0
  24. backtracking(0)
Success #stdin #stdout 0.06s 14124KB
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https://ideone.com/sLw3kv
language:
Python 3 (python  3.12)
created:
4 hours ago
visibility:
public

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