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<?php
$year=2036;
if($year%400==0 || ($year%100!=0 && $year%4==0))
echo $year.' is Leap Year';
else echo $year.' is Not a Leap Year';
?>

Success #stdin #stdout 0.02s 26116KB

stdin

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Standard input is empty

stdout

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2036 is Leap Year

https://ideone.com/qfEaVf

language:

PHP (php 7.3.5)

created:

visibility:

public

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